Question

Calcule:
a) Log 1000 b) Log 32 c) Log 49

Answer 1

$a) log1000 = x\\\\ 10^{x} = 1000\\\\ 10^{x} = 10^{3}\\\\ x = 3$


$b) log32\\\\ log(2^{5} )\\\\ 5.log(2)\\\\ 5.0,3 = 1,5(aproximadamente)$


$c) log49\\\\ log(7^{2} )\\\\ 2.log(7)\\\\ 2.0,85 = 1,69(aproximadamente)$

Espero ter ajudado!