Question

Me ajudem por favor!!

Answer 1

Usando teorema de Tales

$\frac{x}{x + 2} = \frac{9}{12} \\ \\ 9(x + 2) = 12x \\ \\ 9x + 18 = 12x \\ \\ 12x - 9x = 18 \\ \\ 3x = 18 \\ \\ x = \frac{18}{3} = > x = 6$

a) x = 6

b)
AC = x + x + 2
AC = 6 + 6 + 2
AC = 12 + 2
AC = 14