Question

inequação
2x^2+4-48≥0

Answer 1

Olá

$2x {}^{2} + 4 - 48 \geqslant 0$

$2x {}^{2} - 44 \geqslant 0$

$2(x {}^{2} - 22) \geqslant 0$

$x {}^{2} - 22 \geqslant 0$

$x { }^{2} - 22 = 0$

$x = \sqrt{22}$

$x = - \sqrt{22}$

$1(x - \sqrt{22}) \times (x - ( - \sqrt{22))} \geqslant 0$

$(x - \sqrt{22} ) \times (x + \sqrt{22} \geqslant 0$

{ x - √22 ≥ 0
{ x + √22 ≥ 0

{ x - √22 ≤ 0
{ x + √22 ≤0

{ x ≥ √22
{ x ≥ - √22

{ x ≤ √22
{ x ≤ - √22

x € [√22, + infinito
x€ [- infinito, -√22]

x€ [- infinito, √22] u [ √22, + infinito ]


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