Question

determine a funcoa do 1 graul cujo o grafico passa pelos pontos.em seguida encontre a raiz dessa funcao A)a=(1,3) e b=(0,1) B)a=(1,2) e b(0,3)

Answer 1

A) a(1; 3) b(0; 1)
$(y_{f}-y_{i})=m(x_{f}-x_{i}) \\ \\ (3-2)=m(0-1) \\ \\ m= \frac{1}{-1} =-1 \\ \\ (y_{f}-y_{i})=m(x_{f}-x_{i}) \\ \\ (y-2)=(-1)(x-1) \\ \\ y=-x+1+2\\\\ y=-x+3\\\\ f(x)=-x+3\\\\ calculo da raiz\\\\ 0=-x+3\\\\ x=3$

B) a(1; 2) b(0; 3)

 $\\ \\ (1-3)=m(0-1) \\ \\ m=(-2)/(-1) \\ \\ m=2 \\ \\ (y_{f}-y_{i})=m(x_{f}-x_{i}) \\ \\ (y_{f}-3)=2(x_{f}-1) \\ \\ y=2x-2+3 \\ \\ y=2x+1 \\ \\ f(x)=2x+1 \\ \\ calculo da raiz \\ \\ 0=2x+1 \\ \\ x= \frac{-1}{2} =-0,5$