Question

fórmula de bhaskara 3x-4x-2= -3

Answer 1

3x-4x-2=-3
3x-4x-2+3=0
3x-4x+1=0

Delta= b²-4*a*c
D= (-4)²-4*3*1
D= 16-12
D= 4

x = -(b) +- √D /2a
x = -(-4) +- √4 /2*3
x = 4 +- 2 / 6

x' = 4 + 2 / 6 --> 6/6 = 1

x" = 4 -2 / 6 --> 2/6 = 1/3

par ordenado (1, 1/3)

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Answer 2

3x^2 - 4x - 2 = - 3
3x^2 - 4x - 2 + 3 = 0
3x^2 - 4x + 1 = 0
a= 3; b = - 4; c = 1
∆ = b^2 - 4ac
∆ = (-4)^2 - 4.3.1
∆ = 16 - 12
∆ = 4

x = [-b +/- √∆]/2.3
x = [ -(-4) +/- √4\]/6
x' = [ 4 + 2]/6 = 6/6 = 1
x" = [4 - 2]/6 = 2/6 (:2)/(:2) = 1/3

R.: ( 1/3 ; 1)