Question

dada a expresão: x²-x-6=0 encontre o discriminante(delta) e resolva a fórmula da baskhara: -b+/- √Δ/ 2.a

Answer 1

${x}^{2} - x - 6 = 0 \\ a)1 \\ b) - 1 \\ c ) - 6 \\ delta = ( { - 1})^{2} - 4 \times 1 \times ( - 6) \\ delta = 1 + 24 \\ delta = 25 \\ x = \frac{ - ( - 1) + - \sqrt{25} }{2 \times 1} \\ \\ \frac{1 + - 5}{2} \\ x. = \frac{1 + 5}{2} = \frac{6}{2} = 3 \\ x.. = \frac{1 - 5}{2} = \frac{ - 4}{2} = - 2 \\(3.-2)$

Answer 2

x²-x-6=0
a = 1; b = - 1; c = - 6
∆ = b^2-4ac
∆ = (-1)^2 - 4.1.(-6)
∆ = 1 + 24
∆ = 25

x = [ - b +/- √25]/2/1
x = [-(-1) +/- 5]/2

x' = [1+5]/2 = 6/2 = 3
x" = [1-5]/2 = - 4/2 = -2