Question

TEM UM DOIS ECIMA DO parente PERTO DO TRES ( X - 3) + 4 ( X + 1) ( X +6 ) = 180        DELTA  

Answer 1

$(x - 3)^2 + 4 (x + 1) (x + 6) = 180 \\ \\ x^2 - 6x + 9 + 4(x^2 + 7x + 6) = 180 \\ \\ x^2 - 6x + 9 + 4x^2 + 28x + 2 4 = 180 \\ \\ 5x^2 + 22x + 33 = 180 \\ \\ 5x^2 + 22x + 33 - 180 = 0 \\ \\ => 5x^2 + 22x - 147 = 0$

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$\triangle = b^2 -4*a*c$

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a=5, b=22, c=−147

Δ=b²−4ac
Δ=(22)²−4*5*−147
Δ=484+2940
Δ=3424

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$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

$x = \dfrac{-22 \pm \sqrt{3424}}{2*5} \\ \\ \\ x = \dfrac{-22 \pm 2\sqrt{214}}{10} \\ \\ \\ x' = \dfrac{-11 + 2\sqrt{214}}{5} \\ \\ \\ x'' = \dfrac{-11 - 2\sqrt{214}}{5}$


S = {$\dfrac{-11 + 2\sqrt{214}}{5}, \ \ \dfrac{-11 + 2\sqrt{214}}{5}$}