Question

Calcule o perímetro do triângulo de vértices A(8,2), B(3,7), C(2,1)

Answer 1

A(8,2), B(3,7), C(2,1)

A-B=8-3=5 ; 7-2=5

Ab²=5²+5²=25+25=50=

√50=5√2

BC²

b-c= 3-2=1; 7-1=6

1²+6²=1+36=37

√37

A-C

Ac²

8-2=6; 2-1=1

6²+1²=36+1=37

√37=

P= 5√2+√37+√37=

P=5√2+2√37=

P=5 .1,41+2x6,08

P=7,05 +12,16

P=19,21

Answer 2

Boa tarde

sejam os pontos A(8,2), B(3,7), C(2,1)

AB² = 5² + 5² = 50

AB = 5√2

AC² = 6² + 1² = 37

AC = √37

BC² = 1² + 6² = 37

BC = √37

perimetro

P = AB + AC + BC

P = 5√2 + √37 + √37

P = 5√2 + 2√37

P = 19.2366