Question

se x^2+y^2=86 e ab=20 quanto vale (x+y)^2
urgente

Answer 1

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {( x + y)}^{2} = {x}^{2} + {y}^{2} + 2 \times 20 \\ {(x + y)}^{2} = 86 + 40 = 126$