Question

1)Sendo
$y = \frac{ {40}^{10} . {16}^{ - 3}. {8}^{ - 2} }{32}$
a metade do valor de Y será?

Answer 1

y =[ (40)¹⁰ * ( 16)⁻³ * ( 8)⁻²]/ 32

40 = 2² * 10

16 = 2² * 2²

8 = 2² * 2¹

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