Question

resolva:a) (27+3×7)^2÷{4×[800-(9×2+10)^2]} Por favor me ajudem,é para amanhã

Answer 1

a)

(27+3×7)^2÷{4×[800-(9×2+10)^2]}

(27+3×7)^2÷{4×[800-(28)^2]}

(27+3×7)^2÷{4×[800-784]}

(27+3×7)^2÷{4×[16]}

(27+3×7)^2÷{64}

(48)^2÷64

2304÷64 = 36