Question

RESOLVA ( 2 X - 5 ) ( X - 2 ) = - ( X + 2 ) ( 1 - X ) - 4 DELTA

Answer 1

$(2x - 5) (x - 2) = - (x + 2)(1-x) - 4 \\ \\ \\ 2x^2 - 9x + 10 = x^2 + x - 2 - 4 \\ \\ 2x^2 - 9x + 10 = x^2 + x - 6 \\ \\ 2x^2 - 9x + 10 - x^2 - x + 6 = 0 \\ \\ x^2 - 10x + 16 = 0$

a=1, b= −10, c=16

Δ=b²−4ac
Δ=(−10)²−4*1*16
Δ=100−64
Δ=36

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

$x = \dfrac{-(-10) \pm \sqrt{36}}{2*1} \\ \\ \\ x = \dfrac{10 \pm 6}{2} \\ \\ \\ x' = \dfrac{10 + 6}{2} \\ \\ \\ x' = \dfrac{16}{2} \\ \\ \\ x' = 8 \\ \\ \\ x'' = \dfrac{10 - 6}{2} \\ \\ \\ x'' = \dfrac{4}{2} \\ \\ \\ x'' = 2$


S = {8,  2 }