Question

Calcule com Δ = b²-4ac e x = – b ± √Δ

2.a .


-3x²+6x=0

Answer 1

-3x²+6x=0
3x.(-x+2)=0
3x = 0; x = 0/3; x = 0
-x+2= 0
2 = x
X=2

R.: (0,2)

Ou

-3x²+6x=0
a = - 3; b = 6; c = 0
∆ = b^2-4ac
∆ = 6^2-4.(-3).0
∆ = 36

x = [-b +/- √∆]/2.a

x = [-6 +/- 36]/2.(-3)
x = [-6 +6]/(-6) = 0/(-6) = 0
x = [-6-6]/(-6) = -12/(-6) = 2

R.: (0,2)