Question

(4×+1)ao quadrado =(3×-7)ao quadrado

Answer 1

4x+1 . 4x+1 = 16x^2+8x+1

3x-7 . 3x-7 = 9x^2-42x+49

16x^2+8x+1 = 9x^2-42x+49

16x^2+8x +1 -9x^2 + 42x - 49

7x^2+50x-48=0

2500+1344

Δ=3844

-50-/+√Δ ÷ 14

-50 +/-62 ÷ 14

x1=-112 ÷ 14= -8

x2= 12 ÷ 14= 12/14 simplificando 6/7