Question

Dada a P.A (3,7,11,...). Qual a soma dos 50 primeiros termos dessa sequência?

Answer 1

7 - 3 = 4

RAZAO = +4

3, 7, 11, 15, 19, 23, 27, 31, 35, 39, 43, 47, 51, 55, 59, 63, 67, 71, 75, 79, 83, 87, 91, 95, 99, 103, 107, 111, 115, 119, 123, 127, 131, 135, 139, 143, 147, 151, 155, 159, 163, 167, 171, 175, 179, 183, 187, 191, 195, 199,

SOMA= 5.050

Espero Ter ajudado

Answer 2

Sn= (A1+An).n/2

R= 7-3 = 4

A50= A1+(n-1).R
A50= 3+49.4
A50=199

S50= (3+199).50/2
S50= 202.25
S50= 5.050