Question

Fatore os trinômios quadrados perfeitas
a)m^2-14m+49
b)9a^2-6a+1
c)49a^4-28a^2b+4b^2
d)400x^2+200xy+25y^2
e)x^6a^2-8x^3a+16

Answer 1

$a) {m}^{2} - 14m + 49 = {(m - 7)}^{2} = (m - 7)(m - 7) \\ \\ b)9 {a}^{2} - 6a + 1 = {(3a - 1)}^{2} = (3a - 1)(3a - 1) \\ \\ c)49 {a}^{4} - 28 {a}^{2} b + 4 {b}^{2} = {(7a - 2b)}^{2} = (7a - 2b)(7a - 2b) \\ \\ d)400 {x}^{2} + 200xy + 25 {y}^{2} = {(20x + 5y)}^{2} = (20x + 5y)(20x + 5y) \\ \\ e) {x}^{6} {a}^{2} - 8 {x}^{3} a + 16 = {( {x}^{3} a - 4)}^{2} = ( {x}^{3} a - 4)( {x}^{3} a - 4)$