Question

Temos duas expressoes numericas:c={[(2³.√16+3)/7+(³√27.15/5).3].2-(19-7)/√36}.2+12d={[(³√125+3).12]/[(5-√9).2²]}o resultado da soma de c- d e igual a ???????

Answer 1

$c=\{[(2^3.\sqrt{16}+3)/7+(\sqrt[3]{27}.15/5).3].2-(19-7)/\sqrt{36}\}.2+12\\ d=\{[(\sqrt[3]{125}+3).12]/[(5-\sqrt{9}).2^2]\} \\\\ c=\{[(8.4+3)/7+(9.15/5).3].2-(19-7)/6\}.2+12\\ d=\{[(5+3).12]/[(5-3).4]\}\\\\ c=\{[(32+3)/7+27.3].2-12/6\}.2+12\\ d=\{[(5+3).12]/[(5-3).4]\} c=\{[35/7+81].2-2\}.2+12\\ d=\{[8.12]/[2.4]\}\\\\ c=\{[5+81].2-2\}.2+12\\ d=\{96/8\}\\\\ c=\{86.2-2\}.2+12\\ d=12\\\\ c=\{172-2\}.2+12\\ d=12\\\\ c=170.2+12\\ d=12\\\\ c=340+12\\ d=12\\\\ c=352\\ d=12$