Question

x²-8x-12=0 alguem resolve pra mim ?

Answer 1

x²-8x-12=0

a=1; b=-8; c=-12

∆=b²-4ac
∆=(-8)²-4.1.(-12)
∆=64-(-48)
∆=64+48
∆=112

x1 ^ x2= (-b±√∆)÷2a
x1 ^ x2= (8±√112)÷2.1
x1 ^ x2=(8±10,58)÷2
x1=18,58÷2=9,29 ^
x2=(-2,58)÷2=-1,29