Question

Determine o número de termo da P.G 16,32,8192

Answer 1

Olá Jailson!

$PG (16,32,...8192)\\\\a1=16\\\\n=?\\\\r=2\\\\an=8192\\\\an=a1.r^{n-1}\\\\\\8192=16.2^{n-1} \\ \\ 8192/16=2^{n-1}\\ \\ \\ 512=2^{n-1}\\ \\ \\ \\ 512|2\\ 256|2\\ 128|2\\ 64|2\\ 32|2\\ 16|2\\ 8|2\\ 4|2\\ 2|2\\ \\ =2^{9}\\ \\ 2^{9}=2^{n-1} \\ \\ 9=n-1\\ \\ 10=n$

Portanto são 10 termos!

Espero ter ajudado!