Question

como resolver a fração sabendo que log 2 = 0,3010 e log 3 = 0,4771 log c = a:
log raiz cúbicade 24 sobre 2

Answer 1

$log\ \frac{ \sqrt[3]{24}}{2}=log\ 24^{\frac{1}{3}}-log\ 2\\\\\ \frac{1}{3}log\ 24-log\ 2\\\\\ \frac{1}{3}(3log\ 2+log\ 3)-log\ 2\\\\\ \frac{1}{3}(0,9030+0,4771)-0,3010\\\\\ 0,4600-0,3010\\\\ \boxed{0,1590}$