Question

Resolva a equação no campo do ComplexoX²-4x+5=0

Answer 1

x²-4x+5 = 0

∆ = b²-4ac
∆ = (-4)²-4×1×5
∆ = 16-20
∆ = -4

X = (-b±√∆) ÷ 2×a
X = (4±2i) ÷ 2×1

X' = 2+i e X" = 2-i

Answer 2

${x}^{2} - 4x + 5 = 0 \\ \\ delta = 16 - 4 \times 5 = 16 - 20 = - 4 \\ \\ x = \frac{4 + \sqrt{ - 4} }{2} = \frac{4 + 2i}{2} = 2 + i \\ \\ x = \frac{4 - \sqrt{ - 4} }{2} = \frac{4 - 2i}{2} = 2 - i$


S = {2 + i, 2 - i}