Question

resolva a equação: 4y^2-4raiz de 3 y +3=0

Answer 1

$4y^2-4\sqrt{3} y+3=0\\ \\ a=4\\ b=-4\sqrt{3} \\ c=3\\ \\ \Delta=b^2-4ac\\ \Delta=(-4\sqrt{3} )^2-4(4)(3)\\ \Delta=16(3)-4(12)\\ \Delta=48-48\\ \Delta=0\\ \\ x={-b\pm\sqrt{\Delta} \over2a}={-(-4\sqrt{3} \pm\sqrt{0} \over2(4)}={4\sqrt{3} \over8}={\sqrt{3}\over2} \\ \\ S=\{\frac{\sqrt{3}}{2} \}$

Answer 2

4y^2 - 4raiz de 3 y +3=0
4y^2 - 4√3 y + 3 = 0
a= 4; b = - 4√3 ; c = 3
∆ = b^2-4ac
∆ = (-4√3)^2 - 4.4.3
∆ = (16.3) - 16.3
∆ = 48 - 48
∆ = 0
Y = [ - b +/- √∆]/2a
Y = [ - (-4√3) +/- √0]/2.4
Y = 4√3/8 (:4)/(:4)
y = √3/2

R.: y = √3/2