Question

y ao quadrado +2y - 8 =0

Answer 1

y^2+2y-8=0
A=1
B=2
C=-8
Delta=b^2-4ac
Delta=2^2-4.1.(-8)
Delta=4+32
Delta=36
y= 2-6/2 y=-4/2 y=-2
y^2= 2+6/2 y^2=8/2 y^2=4

Answer 2

y² + 2y - 8 = 0

Δ = b² − 4ac

Δ = (2)² −4⋅(1)⋅(−8)

Δ = 4 + 32

Δ = 36

$y = \dfrac{-b \pm \sqrt{\Delta}}{2 . a}\\ \\ \\ y = \dfrac{-(2) \pm \sqrt{36}}{2 . 1}\\ \\ \\ y = \dfrac{-2 \pm 6}{2}\\ \\ \\ y' = \dfrac{-2 - 6}{2}\\ \\ \\ y' = \dfrac{- 8}{2}\\ \\ \\ y' = -4\\ \\ \\ y'' = \dfrac{-2 + 6}{2}\\ \\ \\ y'' = \dfrac{6}{2}\\ \\ \\ y'' = 2$

S = {-4, 2}