Question

[(5-6)²+(7-8)3]x(-2) = ??

Answer 1

Se for:

[(5-6)^2+(7-8)^3]×(-2)
[(-1)^2+(-1)^3]×(-2)
[1+(-1)]×(-2)
0×(-2) = 0

Se for:

[(5-6)^2+(7-8)×3]×(-2)
[(-1)^2+(-1)×3]×(-2)
[1+(-3)]×(-2)
-2×(-2) = 4