Question

[(5-6)²+(7-8)³]x(-2) =??
ajuda pfv

Answer 1

[(5-6)^2+(7-8)^3]x(-2)=?

[(-1)^2+(-1)^3]x(-2)=

[1+(-1)]x(-2)=

[1-1]x(-2)=

[0]x(-2)= 0

Answer 2

OLÁ!

[(5-6)²+(7-8)³]x(-2)=
[(1)²+(-1)³]x(-2)=
[1+-1]x(-2)=
0x(-2)=
= 0

BONS ESTUDOS!!:-) :D