Respostas
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1
x=1 –y
3(1–y)–5y=–17
3–3y–5y=–17
–8y=–17–3 · (–1)
8y=20
y=20/8
y=5/2
x=1–y
x=1–5/2
x=(2–5)/2
x=–3/2
S={–3/2;5/2}
3(1–y)–5y=–17
3–3y–5y=–17
–8y=–17–3 · (–1)
8y=20
y=20/8
y=5/2
x=1–y
x=1–5/2
x=(2–5)/2
x=–3/2
S={–3/2;5/2}
becalc:
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