Question

Fórmula de bhaskara x na 2 + 10x +25= 0

Answer 1

Boa Tarde,

X² + 10x + 25 = 0

a = 1

b = 10

c = 25

Δ = b² - 4ac

Δ = 10² - 4*1*25

Δ = 100 - 100

Δ = 0 (Apresenta apenas uma raiz real)

X = -b +/- √Δ / 2a

X = -10 +/- √0 / 2*1

X = -10 +/- √0 / 2

x = -10 + 0 / 2 = -10/2 = -5

Espero ter ajudado :)

Answer 2

x² + 10x + 25 = 0

a = 1

b = 10

c = 25

Δ = b² - 4 . a . c

Δ = 10² - 4 . 1 . 25

Δ = 100 - 100

Δ = 0

Δ = 0 existe apenas uma raiz :

$\mathtt{\dfrac{-b+-~\sqrt{\Delta}}{2~.~a}~~=~~\dfrac{-10+-~\sqrt{0}}{2~.~1}~~=~~-\dfrac{10}{2}~~=~~-5} \\ \\ \\ \boxed{\boxed{\mathtt{Resposta: -5}}}$