Question

resolver a equaçao do 2 grau
f(x)=-x2+8x-12

Answer 1

Fórmula de Bhaskara:

-x² + 8x - 12 = 0

Δ = b² - 4ac

Δ = 64 - ( 4 . -1 . -12)

Δ = 64 - (48)

Δ = 16

x1 = (-b + √Δ)/2a

x1 = (-8 + √16)/-2

x1 = (-8 + 4)/-2

x1 = 2

x2 = (-b - √Δ)/2a

x2 = -8 - √16)/-2

x2 = (-8 - 4)/-2

x2 = -12/-2

x2 = 6

S = {2,6}

Answer 2

a = -1 , b = 8, c = -12

achando delta

delta = b² - 4 . a . c

delta = 64 - 4 . (-1) . (-12)

delta = 64 - 48

delta = 16

x = -b +ou - raiz de delta /2 . a

x1 = - 8 + 4/ - 2 = - 4/ - 2 = 2

x2 = - 8 - 4/ - 2 = - 12/ -2 = 6

fx = a (x - x1) (x - x2)

fx = - 1 . (x - 2) . (x - 6)