Question

calcule a) 2a/7x.3bxy b)x4/3y.2x3/5y2

Answer 1

$\dfrac{2a}{7x} . 3bxy\\ \\ \\ \dfrac{2a .(3bxy)}{7x} \\ \\ \\ \dfrac{6abxy}{7x} \\ \\ \\ => \dfrac{6aby}{7}$

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$\dfrac{x^4}{3y} . \dfrac{2x^3}{5y^2} \\ \\ \\ \dfrac{x^4 . 2x^3}{3y . 5y^2}\\ \\ \\ \dfrac{2x^7}{5y^3}\\ \\ \\ => \dfrac{2x^7}{5y^3}$