Question

sabendo que log 5 base 12 = a calcule:
Log 144 base 125
ajudae manos

Answer 1

=$log_{5^3}(12^2)$

=$\frac{2}{3}.log_{5}(12)$

que daria aprox: 1,02

Answer 2

log₁₂5 = a ⇒ 12ᵃ = 5

então, log₅12 ⇒ $5^{\frac{1}{a}} = 12$ ⇒ $log_{5} 12 = \frac{1}{a}$

log₁₂₅144 = ?

$log_{125}144 = 2\ log_{125}12$

$2\ log_{125}12 = 2(\frac{log_{5}12}{log_{5}125})$

$2\ log_{125}12 = 2(\frac{\frac{1}{a}}{3})$

$2\ log_{125}12=\frac{2}{3a}$

$log_{125}144 = \frac{2}{3a}$