Question

resolva
${2x }^{2} - 3x = 2x - 1$

Answer 1

Olá!!

Resolução!!

2x² - 3x = 2x - 1
2x² - 3x - 2x + 1 = 0
2x² - 5x + 1 = 0

a = 2, b = - 5. c = 1

∆ = b² - 4ac
∆ = ( - 5 )² - 4 • 2 • 1
∆ = 25 - 8
∆ = 17

x = - b ± √∆ / 2a
x = - ( - 5 ) ± √17/2 • 2
x = 5 ± √17/4
x' = 5 + √17/4
x" = 5 - √17/4

S = { 5 - √17/4, 5 + √17/4 }

Espero ter ajudado!!

Answer 2

2x² -5x +1 = 0

$\mathsf{\Delta=b^2-4ac}$

25 -8 = 17

$\mathsf{x = \frac{-b \pm \sqrt{\Delta} }{2a}}$

5 ± √17/4

{5 + √17/4 , 5 - √17/4}