Question

Resolva a Equação:

Log (3x-5) base (x-1) = 2

Answer 1

Log (3x-5) base (x-1) = 2

$log_{x-1}(3x-5) = 2\\\\ (x-1)^2=3x-5\\\\ x^2 -2x+1=3x-5\\\\ x^2-5x+6=0\\\\ Delta=25-4*1*6 = 1\\\\ x'=(5+1)/2 = 3\\\\ x''=(5-1)/2 = 2$

Espero ter ajudado!