Question

Quanto é: (x²-3x) (2x-1)

Answer 1

(x²-3x) (2x-1)= > (2x³-x²-6x²+3x)=> (2x³-7x²+3x)

resp= 2x³-7x²+3x

Answer 2

Faça primeiro a distributiva

$(x^{2} -3x) .(2x-1)$

ficando

$x^2.2x - x^2 - 6x^2 +3x$

$2x^3 -7x^2 +3x$

ok