Question

utilizando o teorema de pitagoras determine o valor de x nos triângulos retangulos

Answer 1

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a) h²= c² + c²

20²= (3x)² + (4x)²

400= 9x² + 16x²

400= 25x²

400/25= x²

x²= 16

x= √16

x= 4

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b) h²= c² + c²

(x+1)²= (√7)² + x²

x²+2*x*1 + 1²= 7 + x²

x²+2x - x² = 7 - 1

2x= 6

x= 6/2

x= 3

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c) h²= c² + c²

(3√5)²= 6² + x²

9*5= 36 + x²

40= 36 + x²

x²= 40 -36

x²= 4

x= √4

x= 2

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d) h²= c² + c²

(3√2)²= x² + x²

9*2= 2x²

18= 2x²

18/2= x²

x²= 9

x= √9

x= 3

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Espero ter ajudado!!!