Question

(x-3)^=2x^ baskara me ajudem pfvr

Answer 1

x²-6x+9 = 2x²
x²-2x²-6x+9 = 0
-x²-6x+9 = 0
-x²-6x+9 = 0

∆ = (-6)²-4(-1)(-9)
∆ = 36-36
∆ = 0

x = -b/2a
x = -(-6)/2(-1)
x = 6/-2
x = -3

Answer 2

x²-6x+9 = 2x²
x²-2x²-6x+9 = 0
-x²-6x+9 = 0
-x²-6x+9 = 0

∆ = (-6)²-4(-1)(-9)
∆ = 36-36
∆ = 0

x = -b/2a
x = -(-6)/2(-1)
x = 6/-2
x = -3