Question

Determine as coordenadas do vértice nos casos a seguir:

Answer 1

-x²+2x-3

a=-1 b=2 c=-3

Δ=b²-4ac

Δ=2²-4*(-1)*(-3)

Δ=4-12

Δ=-8

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Xv= (-b) / 2*a

Xv=(-2) 2*1

Xv=-2/2

Xv=-1

Yv= (-Δ) /4a

Yv= -( -8) /4*1

Yv= 8/4

Yv= 2

( Xv=-1 e Yv= 2 )

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2x²-6x+5

a=2 b=-6 c=5

Δ=b² -4ac

Δ=(-6)²-4*2*5

Δ=36-40

Δ=-4

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Xv= (-b) / 2*a

Xv=-(-6) 2*2

Xv=-6/4

Xv=-6/4⇒-3/2

Yv= (-Δ) /4a

Yv=-( -4) /4*2

Yv= 4/8

Yv= 4/8 ⇒2/4

(Xv=-3/2 e Yv=2/4)