Question

Em formula de Bhaskara
(2x-3)(x-8)=34

Answer 1

$(2x- 3) (x - 8) = 34 \\ \\ 2x^2 - 19x + 24 = 34 \\ \\ 2x^2 - 19x + 24 - 34 = 0 \\ \\ => 2x^2 - 19x -10 = 0$


$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$


a=2, b=−19, c=−10

Δ=b²−4ac
Δ=(−19)²−4*2*−10
Δ=361+80
Δ=441


$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a}$

$x = \dfrac{-(-19) \pm \sqrt{441}}{2*2} \\ \\ \\ x = \dfrac{19 \pm 21}{4} \\ \\ \\ x' = \dfrac{19 + 21}{4} \\ \\ \\ x' = \dfrac{40}{4} \\ \\ \\ x' = 10 \\ \\ \\ x'' = \dfrac{19 - 21}{4} \\ \\ \\ x'' = \dfrac{-2}{4} \\ \\ \\ x'' = \dfrac{-1}{2}$


S = {$10, \ \ \dfrac{-1}{2}$}