Question

Esboce o grafico da função quadrática
f (x)=x^2+9
y=x^2+4x

15 pontos

Answer 1

f (x)=x^2+9

a= 1

b=0

c=9

Δ=b²-4ac

Δ=0²-4*1*9

Δ=0-36

Δ= -36

Δ<0 sem raizes

Vertices;

Xv=-b/2a -0/2*1 -0/2 = 0

Yv=-Δ/4a - (-36) /4*1 36/4 = 9

__________________________

y=x^2+4x

a=1

b=4

c=0

Δ=b² -4ac

Δ=4²-4*1*0

Δ=16-0

Δ=16

x=-b+-√Δ /2a

x=-4+-√16 /2*1

x=-4+-4 /2

x'= -4+4 /2 = 0/2=0

x''=-4-4 / 2 =-8/2 = -4

vertices;

Xv=-b/2a = -4 /2*1 = -4/2 = -2

Yv = -Δ/4a = -16/4*1 =-16/4 = -4