Question

A ) Mdc 55 325
B ) Mdc 64 , 80 , 52
C ) Mmc 49 15
D ) Mmc 12,14,16

Obs : Usando decomposição simultanea em Fatores primos

Answer 1

A ) Mdc 55 325 = 5

55,325: 5 (#)
11, 65: 5
11,13: 11
1, 13: 13
--------
1,1 = 5

R.: 5

B ) Mdc 64 , 80 , 52 = 4

64, 80, 52: 2 (#)
32, 40, 26: 2 (#)
16, 20, 13: 2
8, 10, 13: 2
4, 5, 13: 2
2, 5, 13: 2
1, 5, 13: 5
1, 1, 13: 13
-----------------
1,1,1 = 2.2 = 4

R.: 4

C ) Mmc (49,15) = 735

49,15 : 3
49,5: 5
49,1: 7
7,1: 7
1,1 = 3.5.7.7 = 15.49 = 735

R.: 735

D ) Mmc (12,14,16)

12,14,16: 2
6,7,8: 2
3,7,4: 2
3,7,2: 2
3,7,1: 3
1,7,1: 7
1,1,1 = 2.2.2.2.3.7 = 16.21 = 336

R.: 336