Question

Me ajudeeeeem......

Answer 1

$p(x) = {x}^{3} { - 3x}^{2} + 1$
Logo
$p(1) = {1}^{3}-( 3 \times {1}^{2} ) + 1 \\ p(1) = 1 - 3 + 1 \\ p(1) = - 1$
$p(2) = {2}^{3} - (3 \times {2}^{2} ) + 1 \\ p(2) = 8 - 12 + 1 \\ p(2) = - 3$
$p( - 1) = ( { - 1}^{3} ) - (3 \times {( - 1)}^{2} ) + 1 \\ p( - 1) = - 1 - 3 + 1 \\ p( - 1) = - 3$

$p(0) = {0}^{3} - (3 \times {0}^{2} ) + 1 \\ p(0) = 0 - 0 + 1 \\ p(0) = 1$

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$p(x) = {x}^{2} - x + 1$
Logo

$p(0) = {0}^{2} - 0 + 1 \\ p(0) = 1$
$p( - 2) = ( { - 2}^{2} ) - ( - 2) + 1 \\ p( - 2) = 4 + 2 + 1 \\ p( - 2) = 7$
$p( - 3) = ( { - 3}^{2} ) - ( -3) + 1 \\ p( - 3) = 9 + 3 + 1 \\ p( - 3) = 13$
$p(2) = {2}^{2} + 2 + 1 \\ p(2) = 4 + 2 + 1 \\ p(2) = 7$