Question

$x^{2} - 7x + 12 = 0$

Answer 1

${x}^{2} - 7x + 12 = 0 \\ delta = {b}^{2} - 4 \times a \times c \\ delta = {( - 7)}^{2} - 4 \times 1 \times 12 \\ delta = 49 - 48 \\ delta = 1 \\ \\ x = \frac{ - b \frac{ + }{} \sqrt{delta} }{ 2 \times a} \\ x = \frac{ - ( - 7) \frac{ + }{} \sqrt{1} }{2 \times 1} \\ x = \frac{7 \frac{ + }{}1 }{2} \\ x = \frac{7 + 1}{2} = \frac{8}{2} = 4 \\ e \\ x = \frac{7 - 1}{2} = \frac{6}{2} = 3$