Question

alguém x^2-7x+12=0??????

Answer 1

Euu

Δ=b^2-4ac

Δ=(-7)²-4*1*12

Δ=49-48

Δ=1

x_1=\frac{-(-7)+\sqrt{1}}{2*1}=\frac{7+1}{2}=\frac{8}{2}=4\\ x_2=\frac{-(-7)-\sqrt{1}}{2*1}=\frac{7-1}{2}=\frac{6}{2}=3\\