• Matéria: Matemática
  • Autor: iTzGabrielzinho
  • Perguntado 7 anos atrás

1) Resolva pelo método da substituição


a) { x+y=14
{ x-y=8

b) { 2x-y=23
{ x+3y=22

Respostas

respondido por: Anônimo
1
a) 2x= 22
x=22/2
x= 11
11+y=14
y=14-11
y=3
b) {2x-y=23
{x+3y= 22 (.2)
{2x-y=23
{2x-6y=44 (-1)
{2x-y=23
{-2x+6y=-44
5y=-21
y=-21/5
y= -4,2
x+3.(-4,2)=22
x-12,6=22
x=22+12,6
x= 34,6
respondido por: guilhermeRL
3

Bom Dia!

A)

\left\{\begin{matrix}x+y=14\\x-y=8\\\end{matrix}\right.

_____________________________

\boxed{x+y=14}

\mathbf{x=14-y}

_____________________________

\boxed{x-y=8}

\mathit{14-y-y}=\textup{8}

\textup{14-2y}=\textup{8}

\textup{-2y}=\textup{8-14}

\textup{-2y}=\textup{-6}

\textup{y}=\frac{-6}{-2}

\textbf{\boxed{\boxed{y=3}}}

_____________________________

\boxed{x=14-y}

\textup{x}=\textup{14-3}

\textbf{\boxed{\boxed{x=11}}}

________________________________________________________

B)

\left\{\begin{matrix}2x-y=23\\x+3y=22\\\end{matrix}\right.

_____________________________

\boxed{2x-y=23}

\textup{-y}=\textup{23-2x} *-1

\textup{y}=\textup{-23+2x}

_____________________________

\boxed{x+3y=22}

\textup{x+3}\times\textup{-23+2x}=\textup{22}

\textup{x-69+6x}=\textup{22}

\textup{7x-69}=\textup{22}

\textup{7x}=\textup{22+69}

\textup{x}=\frac{91}{7}

\textbf{\boxed{\boxed{13}}}

_____________________________

\boxed{x=14-y}

\textup{x}=\textup{14-3}

\textbf{\boxed{\boxed{x=11}}}

_____________________________

\boxed{y=-23+2x}

\textup{y}=\textup{-23+2}\times\textup{13}

\textup{y}=\textup{-23+26}

\textbf{\boxed{\boxed{y=3}}}

________________________________________________________

Att;Guilherme Lima


guilhermeRL: Espero ter ajudado! Box duplo; Resposta!
guilhermeRL: Obrigado por ter marcado! (;
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