Question

considere log2=0,3010 e log3=0,4771 calcule. a)log raiz cubica de 60 b)log raiz quarta de 1,2 c)log(0,54)elevado a 0,5 d)log 3000 e)log200 f)log0,0001 g)log5 h)log raiz de 108

Answer 1

letra A)
$log( \sqrt[3]{60} ) = \frac{ log(60) }{3} = \frac{ log(2 \times 3 \times 10) }{3} \\ \frac{ log(2) + log(3) + log(10) }{3} = \frac{0.3010 + 0.4771 + 1}{3} \\ = 0.5927$