Question

Por favor me ajudem?

Answer 1

a) sen30º=c.o./hip.

1/2 = x/10√2

2x=10√2

x =10√2/2

x=5√2

b) sen45°=c.o./hip.

√2/2 = x/5√2

2x=5√2.√2

2x=5√4

2x=5 . 2

x = 10/2

x = 5

c) cos60°=c.a./hip.

1/2=3√3/x

x=2 . 3√3

x = 6√3

d) tg60°=c.o./c.a.

√3 = x/7√3

x = √3 . 7√3

x = 7√9

x = 7 . 3

x = 21