Question

$(x + 3)(x - 1) = 0$

Answer 1

$x^{2} + 2x - 3$

Δ = b2 - 4.a.c

Δ = 22 - 4 . 1 . -3

Δ = 4 - 4. 1 . -3

Δ = 16

x = (-b +- √Δ)/2a

x' = (-2 + √16)/2.1 x'' = (-2 - √16)/2.1

x' = 2 / 2 x'' = -6 / 2

x' = 1 x'' = -3