h) 25-{36-[4+(18-1+10)-(6-2)]}
i) {[23-(6+7-12)]-[(12-6)-(5-2)]}+(12-3+5)=
j) 100-{25+[14-(10+5-4)-(12-3-6)]+75}
arma pra mim
j)=100−{25+[14−(15−4)−(12−3−6)]+75}=
=100−{25+[14−(11)−(12−3−6)]+75}=
=100−{25+[3−(12−3−6)]+75}=
=100−{25+[3−(9−6)]+75}=
=100−{25+[3−(3)]+75}=
=100−{25+[0]+75}=
=100−{25+75}=
=100−{100}=
=0
=100−{25+[14−(11)−(12−3−6)]+75}=
=100−{25+[3−(12−3−6)]+75}=
=100−{25+[3−(9−6)]+75}=
=100−{25+[3−(3)]+75}=
=100−{25+[0]+75}=
=100−{25+75}=
=100−{100}=
=0
Respostas
respondido por:
0
h) =25−{36−[4+(17+10)−(6−2)]}=
=25−{36−[4+(27)−(6−2)]}=
=25−{36−[31−(6−2)]}=
=25−{36−[31−(4)]}=
=25−{36−[27]}=
=25−{9}=
=16
Perguntas similares
6 anos atrás
6 anos atrás
8 anos atrás
9 anos atrás
9 anos atrás
9 anos atrás
={[23−(1)]−[(12−6)−(5−2)]}+(12−3+5)=
={[22]−[(12−6)−(5−2)]}+(12−3+5)=
={[22]−[(6)−(5−2)]}+(12−3+5)=
={[22]−[(6)−(3)]}+(12−3+5)=
={[22]−[3]}+(12−3+5)=
={19}+(12−3+5)=
={19}+(9+5)=
={19}+(14)=
=33