Question

11x47x²-4=0 equação biquadrada

Answer 1

$11x^{4}$ - 7x² - 4 =0

$11x^{4}$ = y² x²=y

11y²-7x-4=0

y=7+-$\sqrt{49-4.11.(-4)}$/2.11

y=7+-$\sqrt{49+176}$/22

y=7+-$\sqrt{225}$

y=7+-15/22

y1=22/22=1

y2=-8/22=-4/11

Agora substituimos y por x²

x²=1

x1= +-$\sqrt{1}$

x1=+-1

x2= +-$\sqrt{-4/11}$