Question

eliminar expoentes negativos e simplificar:

[(1/7)² * 7^-3 ]^2/5


gabarito: 1/49

podem me ajudar, por favor

Answer 1

$[(\frac{1}{7})^2 . 7^{-3} ]^{2/5} =[(\frac{1}{7})^2 . (\frac{1}{7})^{3} ]^{2/5} =[(\frac{1}{7})^5]^{2/5}=(\frac{1}{7})^{5.\frac{2}{5}} =(\frac{1}{7})^2=\frac{1}{49}$