• Matéria: Matemática
  • Autor: natsume100
  • Perguntado 9 anos atrás

3/5 x 27 elevado 1/3 + 9/5 x 27 elevado -2/3

Respostas

respondido por: ProfAmaral
0
 \frac{3}{5} \cdot27^ \frac{1}{3} + \frac{9}{5} \cdot27^{- \frac{2}{3} }\\
\\= \frac{3}{5} \cdot \sqrt[3]{27} + \frac{9}{5} \cdot (\frac{1}{27}) ^{ \frac{2}{3} }\\
\\= \frac{3}{5} \cdot 3 + \frac{9}{5} \cdot\sqrt[3]{( \frac{1}{27})^2}\\
\\= \frac{3}{5} \cdot 3 + \frac{9}{5} \cdot\sqrt[3]{\frac{1}{729}}\\
\\= \frac{9}{5} + \frac{9}{5} \cdot \frac{1}{9}\\
\\= \frac{9}{5} + \frac{9}{45}\\
\\= \frac{9}{5} + \frac{1}{5}\\
\\= \frac{9+1}{5}\\
\\= \frac{10}{5}\\
\\=2
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